Paradise Trinity Day

[Amigoo]

Re: Two 7s of 2 design
( http://aitnaru.org/images/Khristos_Voskrese.pdf )

About golden circle-squaring scalene triangle,
evidence of "marriage" of sqrt(Pi) and sqrt(2),
the meaning of the x:52,x:53 time prompt.

Given (focus on an isosceles right triangle
adjoined to a circle-squaring right triangle,
both creating the scalene triangle):

(sqrt(Pi) x sqrt(2)) / 2
= 1.7724538509055160272981674833411..
x 1.4142135623730950488016887242097..
= 2.506628274631000502415765284811.. / 2
= 1.2533141373155002512078826424055..

Length of bottom line of circle-squaring scalene triangle
= 3.5449077018110320545963349666823.. 2(sqrt(Pi))
= length of side of circle's area square.

Shortest line length (side of circle's inscribed square)
= (2(sqrt(Pi)) / sqrt(2)) x (2/sqrt(Pi))
= (3.5449077018110320545963349666823.. 2(sqrt(Pi))
/ 1.4142135623730950488016887242097..) sqrt2)
x 1.1283791670955125738961589031215.. 2/sqrt(Pi)
= 2.8284271247461900976033774484194.. 2(sqrt(2))

Since length = side of circle's inscribed square,
circle's Diameter = 2(sqrt(2)) x sqrt(2) = 4.0

Given: Area = Pi x radius^2
= 3.1415926535897932384626433832795.. x 2.0^2
= 12.566370614359172953850573533118..
sqrt(12.566370614359172953850573533118..)
= 3.5449077018110320545963349666823..
= length of bottom line of scalene triangle,
a side of the circle's area square.

To confirm ...
3.5449077018110320545963349666823.. 2(sqrt(Pi))
/ 1.2533141373155002512078826424055.. "marriage license"
= 2.8284271247461900976033774484194.. 2(sqrt(2))

Long story short ...
A squared circle requires marriage of sqrt(Pi) and sqrt(2),
making sqrt(2) transcendental "by marriage".

Rod

[Amigoo]

Re: Parallelisms design
(exploration of Two 7s of 2 geometry)

They say ...
Quadrature can be argued on into a parallel universe,
but maintains reality only in select Cartesian circles.

He who has an ear to hear, hears one side of the story.
He who has an eye to see, lacks visual binocularity.
Yet he who has but single mindedness is able to
perceive the box within and without.

Rod ... ...

[Amigoo]

Re: Parallelisms design
Such mysterious geometry

The quadraturial message teases: "You cannot square circles,
but this is what they look like." (found in nature, presumably,
or in some Paradisiacal universe, a bit distant.)

Rod

[Amigoo]

Re: Parallelisms design

… in Constellation CQ of a parallel universe:
“CQ, CQ, calling Cartesian Quadrature”

Obviously, geometry from another universe ...
else what stars, visible from earth, host a dipper
within nested sqrt(2) circles, quadraturial

Rod ... ...

[Amigoo]

Re: Genomial 2:1 design
"Official Zignature (OZ) of quadraturial replication"

Who can tell
A parallel universe, from terra firma, might appear "upside down and backwards";
even having a 2:1 (or 1:2) scale of its earth-tone clone once alone (or vice versa).
Just imagine! a "Mini Me" ... or Mini #MeToo.

Rod

[Amigoo]

Re: Genomial VP design (renamed)

"Official Zignature (OZ) of quadraturial replication
when hosted by Vesica Piscis and 1:2 ratios"

Rod

[Amigoo]

Re: Genomial VP design

Before starting classes at the university, I asked an advanced geometry student to help me map my weekly route to classes. Vesica gave me this laptop version and mysteriously cautioned: "You have to start outside the box if you're ever invited to the Geometers' VP Lounge."

So, I went to the neighborhood market and bought a bag of salted pumpkin seeds (they're white, not liked by birds and squirrels). I had planned to leave a trail of seeds when first entering that campus maze to know my return route. When deep inside the maze the first day, the campus shuttle passed by me and I soon learned that this shuttle always travels by the 8 points of a circle squared (gates on the perimeter of the campus) - just remember your entrance gate.

I never thought about those seeds in later semesters, but found it mysteriously amusing that the campus gardeners had planted sunflowers in some of the strangest places! At the local pub, a philosophy student once opined that the university orchestrated this colorful symbolism to remind struggling students that "the sun will come out tomorrow".

Rod

[Amigoo]

Re: Genomial VP design
(now with campus hyperloop's 8 gates)

Eight pubs along the hyperloop participate in "conservative" after-hours libations,
but which pub is serving freely that night is unknown

With semester travel plans, a barcode is texted daily to select participants.
Display your barcode at the hyperloop gate and ride free to your destination
(unknown until you get there). If you present an incorrect barcode,
AI whispers sweetly "You can't get there from here."

Of course, return travel is free - even from a different hyperloop gate
(in case you stay overnight with an impromptu study partner).

Rod

[Amigoo]

Re: Genomial VP design
(now with campus hyperloop's 8 gates)

AI whispers sweetly "You can't get there from here."

By design or not, this same AI whisper is heard with sex training dolls
regarding the highly desired "First Base" achievement plateau ...
until you qualify. Just Practice! Practice! Practice!

Rod ... ...

[Amigoo]

Re: Taco Pi design

Math recipe to place a slice of Pi, sandwiched precisely in a taco
(the side and hypotenuse of an isosceles right triangle).

Savor all the Pi you want! (there's more and more)

Rod

[Amigoo]

Re: Genomial VP 1:5:7 design

Squared circle geometry now so esoteric that it could have been
observed on the instrument panel of the Roswell craft long ago!
But probably not since squared circles did not exist then.

About "Spacetime: 1,2 (3) 4,5 (6) 7,8 (9) 10,11 (12)" ...

8 points of a circle squared closely align with the numbers of a clock,
providing memorable association with those points on this "compass".
What point is what number 1:5:7 defines right triangle quadrature.

What The clock is upside down and backwards
Not when viewed from space.

Rod ... ...

[Amigoo]

Re: Taco Pi design

To calculate the secret of the Taco Pi recipe ...

Pi-eating sqrt(2) = (2/(2/sqrt(Pi))) / ((sqrt(2)/sqrt(Pi))/2)

Don't enter a Pi-eating contest when sqrt(2) is a contestant.

Rod

[Amigoo]

Re: Taco Pi design

The restated secret of the Taco Pi recipe ...

Pi-eating sqrt(2) = ((sqrt(2)sqrt(Pi))/2) x (2/sqrt(Pi))

... confirming that Pi is "absorbed" by sqrt(2).

Rod ... ...

[Amigoo]

Re: Taco Pi design (now with Taco Pi Junior)

This second set of sqrt(2)-influenced objects maintains
the same ratios as the larger circle.

Rod

[Amigoo]

Re: Taco Pi design (now a sqrt(2) spiral)

This third set of sqrt(2)-influenced objects also maintains
the same ratios as the larger circle.

Rod

[Amigoo]

Re: Taco Pi design (now a sqrt(2) spiral)

Who knew Transcendental Pi is in a bread box:

In a clockwise, 360-degree turn of the sqrt(2) spiral,
line representing sqrt(Pi) decreases by factor of 16:

1.7724538509055160272981674833411..
/ 0.11077836568159475170613546770882.. = 16

Who knew
Pi renews its transcendentalism in a circle squared!

Rod ... ...

[Amigoo]

Re: Taco Pi design

Testing new online file sharing ...

This file: http://aitnaru.org/images/Khristos_Voskrese.pdf
is here also: https://uploadfiles.io/9tfge

Rod

[Amigoo]

Re: Inside Pi Thrice design

"Each of three lines of enclosed golden 'X' is paired
with another line, creating three sqrt(Pi) ratios;
circle-squaring 2/sqrt(Pi) ratio is also present."

Rod

[Amigoo]

Examples of Midwayer prompts sprinkled throughout these studies ...

This morning's "3:18" is a personal prompt for squared circles geometry:
1/Pi = 0.31830988618379067153776752674503.. and then 2(sqrt(1/Pi))
= 1.1283791670955125738961589031215.., defining circle-squaring ratio
of a right triangle: hypotenuse/long side = diameter/side of circle's square.

2/sqrt(Pi) = diameter/side = 1.1283791670955125738961589031215..

... then 3:21 appeared, signaling to me "progress" and "Naturally!"

Rod ... ...

[Amigoo]

Re: E of Q design

"If Euler had prognosticated Quadrature,
2/sqrt(Pi) might have been his 3rd number
since this constant defines squared circles
= 1.1283791670955125738961589031215.."

Rod ... ...

[Amigoo]

Re: E of Q design

2/sqrt(Pi) might have been his 3rd number

Geometers' secret ...
In the red 'X' objects, each red line is paired with a green line
where the lengths ratio = sqrt(Pi); 2/sqrt(Pi) is also present.

Rod

[Amigoo]

Re: E of iQ design

2/sqrt(Pi) might have been his 3rd number

Who knew Quadrature has identifiable DNA (red line)
(and why the design name changed to E of iQ)
Internal ID: 110446-110418

Rod ....... ...

[Amigoo]

Re: E of iQ design

2/sqrt(Pi) might have been his 3rd number

But Pythagoras had first choice of this number with his a^2 + b^2 = c^2
since a circle-squaring right triangle, inscribed in the circle with its hypotenuse
having the same length as circle's diameter, "depletes" Pi's transcendence.

Let Diameter = 2.0 for easy show & tell to the disbelievers.

Rod ... ...

[Amigoo]

Regarding Essence of "impossible" Quadrature (E of iQ) ...

Given: Diameter = 2.0, circle's Area = Pi x radius^2
A = Pi, sqrt(Pi) = SoCS (Side of Circle's Square)
Since a^2 + b^2 = c^2, b^2 = sqrt(4.0 - Pi)

b^2 = 0.8584073464102067615373566167205..
b = 0.92650275035220848584275966758914..
a = 1.7724538509055160272981674833411.. sqrt(Pi)
c = 2.0 circle's Diameter

Therefore, Pi + b^2 = 4.0
3.1415926535897932384626433832795..
+ 0.8584073464102067615373566167205..
= 4.0

Rod

[Amigoo]

About iQuadrature's 2/sqrt(Pi) ...

1.1283791670955125738961589031215..
^2 = 1.2732395447351626861510701069801..

A circle having a diameter of (2/sqrt(Pi))^2
has Side of Circle's Square (SoCS) = 2/sqrt(Pi),
proving the marriage of sqrt(Pi) and sqrt(2)
in a transcendental union!

Rod ... ...