Paradise Trinity Day

[Amigoo]

Re: Qubit_ER Tunnel design
final^7 ... Go figure!

Pop Quiz:
How many sides does the "tunnel" have
(clue: two cubes, sharing one side)
1? 2? 3? ... 7? ... 10? or 11?

Rod

[Amigoo]

Re: Qubit_ER Tunnel design
final^7 ... Go figure!

Pop Quiz:
How many sides does the "tunnel" have

Recovery points for incorrect answers ...
Since a "tunnel" is typically defined as a "passage through",
describe the geometric object of your calculated sides.

Rod ... ...

[Amigoo]

Re: Qubit_ER Tunnel design
"Sqrt(2) and Quadrature"

Displayed online: http://aitnaru.org/threepoints.html

Answers “What’s the point?" about quadrature.
A unique, circle-squaring right triangle contains defining
hypotenuse-to-long-side ratio of 1.1283791670955..
= 2/sqrt(Pi) = sqrt(Pi)/(Pi/2) = 2(sqrt(1/Pi))

Rod

[Amigoo]

Re: Qubit_ER Tunnel design
"Sqrt(2) and Quadrature"

About that '7' ... still dunno!
... but if this qualifies as "sacred geometry",
UB 16:0.1-9 might apply (Seven Master Spirits*)
and "Tunnel" becomes "portal to Paradise".

* http://www.theub.org/part-i.html#P016_0

Rod

[Amigoo]

Re: Point One II design
(sounds like "Point One Too")

Exploration that created another version of the Point One design,
confirming a Center of Quadrature and validating sqrt(2) reality:

If the similar side (top in this design) of two similar, circle-squaring
isosceles trapezoids form hypotenuse and side of an isosceles right triangle,
the two trapezoids, as geometric objects, have a sqrt(2) relationship ...
and Pi values within the trapezoids must have similar relationship.

Rod

[Amigoo]

Re: Point One II design
Added to: http://aitnaru.org/images/Khristos_Voskrese.pdf

Trapezoidal simplicity! (at least, similarity)

Rod ... ...

[Amigoo]

Re: Point One II design
"Trapezoidal simplicity! (at least, similarity)"

Design recolored to highlight the geometric "flutterby"
that identifies Neighborhood's Quadrature Center.

Rod

[Amigoo]

Re: Point One II design

Geometers' secret: Pi is divisible by 2 ... precisely
in this Cartesian Neighborhood where sqrt(2)^2 = 2

Rod ... ...

[Amigoo]

Re: Point One II design
"Pi/2 precision where sqrt(2)^2 = 2"

Geometers' secret: "CoQ" = Center of Quadrature
(formed by light blue arcs and the center circle)

Rod

[Amigoo]

Re: Point One II design
"Cartesian transcendental legerdemain"

Area square of small circle is 1/4 area of large circle ... precisely!
(maybe deck is marked with a circle-squaring right triangle)

Rod ... ...

[Amigoo]

Re: Point One II design
"Cartesian transcendental legerdemain"

Trapezoidal Juxtaposition Clue (JTC): An "open book"
... about the relationship of the inscribed trapezoids
(in circles having sqrt(2) relationship).

JTC also refers to Khristos Voskrese

Rod

[Amigoo]

Re: Transcendental Mean Identified design

After such geometric redundancy in this Cartesian Neighborhood
(for months and months) "TMI Indeed!" comes to mind.

Rod ... ...

[Amigoo]

Re: Sqrt(Pi) Ratios design
aka "Transcendental Mean Identified redux"
aka "TMI ^2"

... from a previous stroll in the Neighborhood.

Rod

[Amigoo]

Re: Flower of Life design

Composition of TMI circle-squaring objects,
especially scalene and right triangles.
(now starting development)

Rod ... ...

[Amigoo]

Re: iamQ design (I Am Quadrature)
"Quadrature defined by marriage of sqrt(Pi) and sqrt(2)"
(inspired while working on Flower of Life design)

Cartesian evidence: Length of Diameter = 2.0,
Length of golden diagonal = (sqrt(Pi) x sqrt(2)) / 2

Rod ... ...

[Amigoo]

Re: iamQ design (I Am Quadrature)
"Quadrature defined by marriage of sqrt(Pi) and sqrt(2)"

With squared circle geometry that speaks for itself,
you get yada, yada, yada of quadraturial persuasion.
Now sqrt(2) wants more focus

"It's all Greek to me" ...

This geometry design might be referring to math's
nonlinear constraint function returning ceq(x).
Heaven knows that the golden quadraturial pretzel
could use some mathematical contraint!

Rod

[Amigoo]

Re: iamQ design (I Am Quadrature)
"Quadrature defined by marriage of sqrt(Pi) and sqrt(2)"

aka "ceq(x) explained" (arc, arc!)
(magenta arc identifies diagonal of the circle's square
having twice the length of golden "pretzel's" diagonal)

"Say what?!" Geometric example of "esoteric".

Rod ... ...

[Amigoo]

Re: https://www.mathsisfun.com/numbers/prim ... o-10k.html

A quick glance at this list reveals (?) that prime numbers
do not end with 0,2,4,5,6,8 (except for numbers 2 and 5).

Such a list might reveal the next significant pattern.

Rod

[Amigoo]

Re: https://www.mathsisfun.com/numbers/prim ... o-10k.html

number is not a prime number if ending 0,2,4,5,6,8
of remaining numbers, not prime if divisible by 3,5,7,9

Rod ... ...

[Amigoo]

Current pattern (seems all-inclusive) ...

Re: https://www.mathsisfun.com/numbers/prim ... o-10k.html

number is not a prime number if ending 0,2,4,5,6,8 (except 2,5)
Of remaining numbers, not prime if evenly divisible by 3,5,7,9,11,13

"Prime Nots" analysis comes to mind.

Rod ... ...

[Amigoo]

Re: https://www.mathsisfun.com/numbers/prim ... o-10k.html

A number is not a prime number if ending 0,2,4,5,6, or 8 (except 2,5)
Of remaining numbers, it's not prime if evenly divisible by 3,5,7,9,11, or 13

"Prime kNots" analysis has better appeal
("knot" refers to group of things)

Rod

[Amigoo]

Re: https://www.mathsisfun.com/numbers/prim ... o-10k.html

A number is not a prime number if ending 0,2,4,5,6, or 8 (except 2,5)
Of remaining numbers, it's not prime if evenly divisible by 3,5,7,9,11, or 13

The golden "pretzel" in iamQ may be a mathematical "prime knot" (not "kNot").
Just start tracing at either end of the diagonal ... in any direction.

Re: https://en.wikipedia.org/wiki/Prime_knot
"Number of prime knots with 5 crossings = 2"
Does this "pretzel" now make three with 5

Rod

[Amigoo]

Re: https://www.mathsisfun.com/numbers/prim ... o-10k.html

A number is not a prime number if ending 0,2,4,5,6, or 8 (except 2,5)
Of remaining numbers, it's not prime if evenly divisible by 3,5,7,9,11, or 13

589 selects as a prime number (it's not) ... unless divided by 19

Maybe this is the better selection (if divisor is not the number):
"not prime if evenly divisible by 3,5,7,9,11,13,15,17, or 19"
since "prime if divisible by itself and 1" is still a rule.

3589 hints that a divisor selection list is required:
3,5,7,9,11,13,15,17,19,21,23,25,27,29,31,33,35,37, ...
with divisors required related to size of number.

Rod

[Amigoo]

Re: https://www.mathsisfun.com/numbers/prim ... o-10k.html

A number is not a prime number if ending 0,2,4,5,6, or 8 (except 2,5)

Of remaining numbers, it's not prime if evenly divisible by:
3,5,7,9,11,13,15,17,19,21,23,25,27,29,31,33,35,37, ...
with divisors required related to size of number.

Even with maximum divisors (all increments up to the number itself),
it should take less calculating energy than searching for a bitcoin.

Rod

[Amigoo]

Re: https://www.mathsisfun.com/numbers/prim ... o-10k.html

A number is not a prime number if ending 0,2,4,5,6, or 8 (except 2,5)
... and a prime times a prime is not a prime.

Rod